Independent work on organic chemistry on the topics:

"Alkanes", "Alkenes", "Alkynes".

Chemistry teacher Zhuravleva T.K.

Independent work on the topic: Alkanes

Option #1

1. Match:

Concept:

1) homologs, 2) isomers.

Definition:

a) substances similar in structure and properties, the composition of which differs by one or more CH 2 groups.

b) substances that have the same composition, but different chemical structures.

2. General formula of alkanes

a) C n H 2 n -6, b) C n H 2 n -2, c) C n H 2 n, d) C n H 2 n +2.

3.

a) C 2 H 8, b) C 2 H 6, c) C 5 H 8, d) C 6 H 6.

Name this substance and write its full structural formula.

4. Find the formula of the pentane isomer:

a) CH 3 -CH-CH 3, b) CH 3 -CH 2, c) CH 2 -CH 2 d) CH 3 -CH 2

│ │ │ │ │

CH 3 CH 3 CH 3 CH 3 CH-CH 3

5. Homologues are substances:

a) C 3 H 8 and C 2 H 2, b) C 5 H 12 and C 3 H 6, c) C 2 H 2 and C 6 H 6, d) CH 4 and C 2 H 6

6. Alkanes are characterized by the following reactions:

a) addition b) substitution c) polymerization.

7. Match:

Alkane formula :

1) CH 3 -CH 2 -CH 2 -CH 2 2) CH 3 -CH 2 -CH 2 -CH 2

CH 3 CH 3 CH 2 - CH 3

Name:

a) 2-methylpentane, b) hexane

Option No. 2

1. Fill in the missing word:

a) Substances that are similar in structure and properties, but whose composition differs by one or more CH 2 groups, are called -___. b) Substances that have the same elemental composition but different chemical structures are called _________.

2. Saturated hydrocarbons have the general formula:

a) C n H 2 n -6, b) C n H 2 n -2, c) C n H 2 n, d) C n H 2 n +2

3. Specify the formula of the saturated hydrocarbon:

a) C 2 H 4, b) C 3 H 4, c) C 4 H 10, d) C 6 H 6.

4. Find the formula for the homologue of butane:

a) CH 3 -CH 2, b) CH 3 -CH 2 -CH-CH 3, c) CH 3 -CH 2 -CH 2 -CH 3

CH 2 -CH 2 -CH 3 CH 3

d) CH 3 -CH -CH 3

5. Homologues are substances of normal structure:

a) CH 4 and C 2 H 4, b) C 3 H 8 and C 5 H 12, c) C 4 H 8 and C 8 H 1 8, d) CH 4 and C 6 H 10

6. Make up the formulas of the isomer and homologue of hexane

7. Match:

Alkane formula: 1) CH 3 -CH 2 -CH-CH 2 CH 2 -CH 3 2) CH 3 -CH 2 - CH-CH-CH 3

C 2 H 5 CH 3 CH 3

Name:

a) 3-ethylhexane, b) 2,3-dimethylpentane

Independent work on the topic: Alkenes.

Option #1

a) homolog; b) isomer;

CH 2 = CH – CH – CH 2 – CH 2 - CH 3

CH 3

CH 3 |

a) CH 3 – CH = C – CH – CH 3 b) CH 2 = C – CH 2 – CH – CH 3

׀ ׀ ׀

CH 3 CH 3 CH 2 – CH 3

3.Obtain an alkene by dehydrogenation of butane.

4.Write the equations of chemical reactions and indicate the type of reactions:

a) CH 2 = CH – CH 3 + H 2 →

b) CH 3 - CH =CH – CH 3 + Br 2 →

c) C 2 H 4 + O 2 →

d) CH 2 = CH -CH 2 + HCl →

Option No. 2

1. Make up structural formulas:

a) homolog; b) isomer;

c) isomer of the position of the double bond.

for a substance having the structure

CH 3 – CH = CH – CH – CH 3

C2H5

2.Name the following hydrocarbons using systematic nomenclature:

CH 3

a) CH 2 = C – CH 2 – CH 2 b) CH 3 – CH= C – C – CH 3

׀ ׀ ׀

CH 3 CH 3 CH 3

3.Obtain propene by dehydration of alcohol.

4.Write the equations of chemical reactions and indicate the type of reaction:

a) CH 2 = CH – CH 2 – CH 3 + H 2 O →

b) CH 2 = CH 2 + H 2 →

c) CH 2 = CH 2 + HCL →

d) C 3 H 6 + O 2 →

Independent work

Unsaturated hydrocarbons.

Alkenes

GRADE 10

This lesson is a lesson in learning new material in the form of a lecture with elements of conversation and independent work of students.
Students work in three groups. In each group there is a teacher assistant who distributes work to each student in this group. Each student has a reminder.

REMINDER

Planned learning outcomes

Know: determination of unsaturated hydrocarbons of the ethylene series, the general formula of alkenes, four types of isomerism of alkenes, their physical and chemical properties, methods of production and areas of application of hydrocarbons of the ethylene series.

Be able to: explain the features of the formation of - and - bonds, write down the molecular, structural and electronic formulas of alkenes, designate the distribution of electron density in the molecule, name the substances of the ethylene series according to systematic nomenclature and write down their formulas using the names of the substances, create formulas for various isomers using the molecular formula of the alkene, write down equations reactions characterizing the chemical properties of alkenes, compare the properties of alkenes with the properties of saturated hydrocarbons, solve problems of finding the molecular formula.

Goals. Educational: learn to deduce the general formula of alkenes, know their physical and chemical properties, be able to write down the molecular and structural formulas of alkenes, name substances according to systematic nomenclature, develop skills in solving problems to find the molecular formula.
Educational: cultivate a desire to learn actively, with interest, instill conscious discipline, clarity and organization in work, work under the motto: “One for all, and all for one.”

Lesson methods and techniques

• Individual work with cards.
• Work in groups and pairs.
• Demonstration chemical experiment.
• Use of technical teaching aids.
• Independent work on drawing up formulas of substances.
• Oral answers at the board.
• Taking notes from the textbook in a notebook.

Lesson topic plan

(written on the board)

1. The structure of the ethylene molecule C 2 H 4.
2. Isomerism and nomenclature of alkenes.
3. Preparation of alkenes.
4. Physical properties.
5. Chemical properties.
6. Application.
7. Genetic connection.

Equipment and reagents. Cards with tasks, a graphic projector and slides, a tripod, a device for obtaining and collecting gases, an alcohol lamp, test tubes, sand, a chemical spoon; ethyl alcohol, potassium permanganate, bromine water, sulfuric acid (conc.).

DURING THE CLASSES

The lesson begins with a conversation in the form frontal poll. The purpose of this part of the lesson is to create a “success situation.” Students understand the questions, they know the answers to them and are actively involved in the work.

1. What is the bond length?

(The bond length is the distance between the centers
nuclei of bonded atoms in a molecule.)

2. What can be said about the carbon-carbon bond length of substances with a single (C–C) and double (C=C) bond?

(Length of carbon-carbon single bond – 0.154 nm
double bond – 0.133 nm, double bond is stronger and shorter than single bond.)

3. How many -bonds can arise between atoms?

4. What can be said about the strength of the bond?

(It is less durable than single - connection.)

5. What chemical bond is formed between hybridized clouds?

6. How many valence electrons does a carbon atom have?

Independent work.
Derivation of molecular formula

Task. In the compound, the mass fraction of carbon is 85.7%, the mass fraction of hydrogen is 14.3%, the density of hydrogen is 14. Derive the molecular formula of the hydrocarbon.
(One of the students decides at the board.)

Given:

(C) = 85.7% (or 0.857),
(H) = 14.3% (or 0.143),
D(H2) = 14.

Find:

C x H y .

Solution

M(C x H y) = 14 2 = 28 g/mol.
For 1 mol C x H y m(C x H y) = 28 g,
m(C) = 28 (g) 0.857 = 24 g,
n(C) = 24 (g)/12 (g/mol) = 2 mol,
m(H) = 28 (g) 0.143 = 4 g,
n(H) = 4 (g)/1 (g/mol) = 4 mol.
The hydrocarbon formula is C 2 H 4.

We conclude that the C 2 H 4 molecule is not saturated with hydrogen atoms.

The structure of the ethylene molecule C 2 H 4

We demonstrate a model of a given hydrocarbon molecule through a graphic projector.

The C 2 H 4 molecule is flat, the carbon atoms forming the double bond are in the state
sp 2-hybridization, bond angle 120°.

We compose a homological series: C 2 H 4, C 3 H 6, C 4 H 8 ... and derive the general formula C n H 2 n .
Let's sum up the stage we've passed.

Isomerism and nomenclature of alkenes

Types of isomerism
1) Consider the structural formulas of linear and branched alkenes having the same molecular formula C 4 H 8:

This type of isomerism is called carbon skeleton isomerism.

2) Isomerism of multiple bond position:

3) Isomerism of different homologous series. General formula C n H 2 n corresponds to two homologous series: alkenes and cycloparaffins. For example, the formula C 4 H 8 may belong to compounds of different classes:

4) Spatial or geometric isomerism. In butene-2 ​​CH 3 – CH = CH – CH 3, each carbon at the double bond has different substituents (H and CH 3). In such cases, cistrans isomerism is possible for alkenes. If the elements of the main carbon chain are on one side of the double bond in the plane of the molecule, then this is cisisomer; if on opposite sides, then this trans isomer:

Independent work using cards (5 min)
Name the substances.

1st group:

2nd group:

3rd group:

The completed independent work is recorded on film and projected through a graphic projector onto the screen. Students exercise self-control.

Preparation of alkenes

1) Dehydration of alcohols (demonstration experience of producing ethylene from ethyl alcohol):

2) Dehydrogenation of alkanes:

3) Pyrolysis and cracking of oil and natural gas:

4) From halogenated alkanes:

Physical properties

Alkenes - ethene, propene and butene - under normal conditions (20 ° C, 1 atm) - gases, from C 5 H 10 to C 18 H 36 - liquids, higher alkenes - solids. Alkenes are insoluble in water, but soluble in organic solvents.

Chemical properties

In organic chemistry, three types of chemical reactions are considered: substitution, addition and decomposition.

1) Alkenes are characterized by addition reactions.

Addition of hydrogen (hydrogenation):

Addition of halogens (laboratory experiment on decolorization of bromine water):

Addition of hydrogen halides:

Markovnikov's rule: hydrogen attaches at the site of a multiple bond to a more hydrogenated carbon, and a halogen to a less hydrogenated one.

For example:

The reaction proceeds by an ionic mechanism.

Addition of water (hydration reaction):

2) Oxidation reactions.

Demonstration experience. Ethene discolors a solution of potassium permanganate, which proves the unsaturated nature of ethene:

Ethylene glycol is used as an antifreeze; it is used to make lavsan fiber and explosives.

Oxidation of ethene on a silver catalyst produces ethylene oxide:

Ethylene oxide is used to produce acetaldehyde, detergents, varnishes, plastics, rubbers and fibers, and cosmetics.

3) Polymerization reaction.

The process of combining many identical molecules into larger ones is called a polymerization reaction.

Determine the molecular formula of a hydrocarbon that contains 85.7% carbon and has a hydrogen density of 21.

Given:

(C) = 0.857 (or 85.7%),
D(H2) = 21.

Find:

Solution

M(C x H y) = D(H2) M(H 2) = 21 2 = 42 g/mol.
For n(C x H y) = 1 mol m(C) = 42 0.857 = 36 g,
n(C) = 36 (g)/12 (g/mol) = 3 mol,
m(H) = 42 – 36 = 6 g,
n(H) = 6 (g)/1 (g/mol) = 6 mol.
The hydrocarbon formula is C 3 H 6 (propene).

Task 3.When 4.2 g of a substance is burned, 13.2 g of carbon monoxide (IV) and 5.4 g of water are formed. The vapor density of this substance in air is 2.9. Determine the composition of the hydrocarbon molecule.

Given:

m(C x H y) = 4.2 g,
m(CO 2) = 13.2 g,
m(H 2 O) = 5.4 g,
D(air) = 2.9.

Find: C x H y .

Solution

M(C x H y) = 2.9 29 = 84 g/mol.
To solve the problem, let's create a reaction equation:

Let's find the mass X mole of CO 2 and the corresponding amount of substance:

m(CO 2) = 84 13.2/4.2 = 264 g,
n(CO 2) = 264 (g)/44 (g/mol) = 6 mol, X = 6.
Likewise m(H 2 O) = 84 5.4/4.2 = 108 g,
n(H 2 O) = 108 (g)/18 (g/mol) = 6 mol, y = 12.
C 6 H 12 – hexene.

Each group submits the tasks they completed on pieces of paper. This is followed by a summary of the lesson.

Homework.Rudzitis G.E., Feldman F.G. Chemistry-10. M.: Education, 1999, chapter IV, § 1, p. 30–38, fig. 10, p. 38. Prepare questions 6, 7 from the plan for studying the lesson topic for the seminar, learn the material of the lesson-lecture.

Independent work№3. Grade 10.

Subject:Alkenes. Ioption.

3-ethylpentene-2; 2,5-dimethylhexene-3.

C6H14, C8H16, C6H6, C3H6, C2H6O, C12H22O11, C5H12, C7H12.

a) hydrogenation of propene;

b) combustion of ethylene;

c) chlorination of butene-1.

_________________________________________________________________________

Independent work No. 3.Grade 10.

Subject:Alkenes. IIIoption.

1. Make up the structural formulas of the following substances:

3-methylpentene-1; 2,3-dimethylbutene-1.

2.Indicate the bond angle, the type of carbon hybridization, and the general formula of alkenes.

3. For butene-2, write down the structural formulas of the cis and trans isomers.

4.Write the reaction equations. Give names to the resulting substances.

a) hydrogenation of propene;

b) elimination of hydrogen halide from 2-chlorobutane;

c) polymerization of ethylene.

____________________________________________________________________________

Independent work No. 3.Grade 10.

Subject:Alkenes.IIoption.

1. Make up the structural formulas of the following substances:

3,3-dimethylbutene-1; 2-methyl-3-ethylpentene-2.

2.Indicate the bond angle, the type of carbon hybridization, and the general formula of alkenes.

3. Select alkene formulas from this list:

C 3 H 4, C 6 H 14, C 8 H 16, C 6 H 6, C 3 H 6, C 2 H 4 O 2, C 6 H 12, C 4 H 6.

4.Write the reaction equations. Give names to the resulting substances.

a) hydrogenation of butene-2;

b) methane combustion;

c) hydration of propene.

____________________________________________ _______________________________

Independent work No. 3. Grade 10.

Subject:Alkenes.IVoption.

1. Make up the structural formulas of the following substances:

2,3,4-trimethylpentene-2; 4,5-dimethyloctene-4.

2.Indicate the bond angle, the type of carbon hybridization, and the general formula of alkenes.

3. Write the structural formulas of all hydrocarbons with the composition C 4 H 8 and name them.

4.Write the reaction equations. Give names to the resulting substances.

a) hydrogenation of ethylene;

b) combustion of propene;

c) interaction of butene-2 ​​with hydrogen bromide.

___________________________________________________________________

Yurgamysh branch

GBPOU "Kurgan Basic Medical College"

Collection of independent works on chemistry

under the section “Unsaturated hydrocarbons”

for specialty 34.02.01 “Nursing”

compiled by chemistry teacher: N.S. Trofimova

Yurgamysh 2017

Independent work

“Alkenes. Composition, structure. Isomerism and nomenclature.

Physical and chemical properties. Relationship with alkanes"

1. Indicate the general formula of alkenes and the general formula of alkanes.

2. Make up structural formulas for the following substances:

3-methylbutene-1

2-methylbutene-1

2,2-dimethylpropane

3. Name the hydrocarbons: A) CH 2 = CH-CH 2 -CH(CH 3) 2 B) (CH 3) 2 CH- C(CH 3) = CH- CH 2 - CH 3

4. Write the structural formula of the isomer 2-methylpentene-1.

5. Write down the structural formula of any homolog of butene-1.

6. What types of isomerism are characteristic of alkenes? Make up the formulas: A) trans-butene-1

B) cis-1-bromopropene

7. Specify the hydrogenation reaction

C 2 H 4 + H 2 → C 2 H 6

C 2 H 4 + H 2 O → C 2 H 5 OH

C 2 H 6 → C 2 H 4 + H 2

C 2 H 4 + Cl 2 → C 2 H 6 Cl 2

8. Why are addition reactions characteristic of alkenes, but such reactions are generally impossible for alkanes?

9. Indicate the correct judgment: A) Markovnikov’s rule - when a hydrogen halide is added to an alkene, hydrogen attaches to the carbon atom at the double bond, to which a larger number of hydrogen atoms are connected; B) a polymer is a high-molecular compound whose molecules consist of many identical structural units.

10. Gas was obtained in the laboratory. In order to establish its structure, it was passed through a yellow bromine solution. The solution became colorless. What hydrocarbons can the resulting gas be classified as and why?

_____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________

11. Purple potassium permanganate solution can be decolorized using

Support your answer with the reaction equation.

12. Solve the circuit:

Na? ? +H 2 O +O 2

chloroethane → butane → chlorobutane → butene-1 → A → ?

14. Compose a polymerization reaction involving butene-2.

15. Give an equation for a chemical reaction that demonstrates Markovnikov’s rule.

Option 1

Write the reaction equation for the production of 2-methylbutene-2 ​​by dehydration of the corresponding alcohol and dehydrohalogenation of the haloalkane.

CH 3 -CH 2 -CH 2 OH→CH 2 =CH-CH 3 →CH 3 -CHCl-CH 3 →CH 3 -CH(CH 3)-CH(CH 3)-CH 3 →CH 3 -C(CH 3)=C(CH 3)-CH 3

What is the structural formula of ethylene hydrocarbon if 11.2 g of it, when reacted with excess HBr, is converted into 27.4 g of bromoalkane with the halogen position at the tertiary carbon atom?

Independent work on the topic “Alkenes”

Option 2

Write the reaction equation for the production of 2,3-dimethylbutene-1 by dehydration of the corresponding alcohol and dehydrohalogenation of the haloalkane.

What reactions can be used to carry out the following transformations? If necessary, indicate the reaction conditions

C 6 H 12 →C 6 H 14 →C 3 H 6 →[ -CH 2 -CH(CH 3)- ] p

Ethylene hydrocarbon weighing 7.0 g decolorizes 640 g of bromine water with a mass fraction of bromine of 2.5%. Determine the molecular formula of the alkene.

Card 1. Topic: Alkenes 1. To classalkenes applies 1) C 2 H 6 2) C 3 H 4 3) C 2 H 4 4) C 5 H 12 2. Alkenes are characterized by isomerism 1) carbon skeleton 2) geometric 3) double bond positions 4) interclass water in the combustion reaction of ethylene 4. As a resulthydrochlorination butene-1 is formed 1) 1-chlorobutane 2) 2-chlorobutane 3) 1-chlorobutene-1 4) 2-chlorobutene-1 5) You can get ethylene by reaction 1) alcohol dehydration 2) dehydrogenation of the alkane 3) cracking 4) polymerization

Card 2. Topic: Alkenes 1. An alkene, the molecule of which contains 6 carbon atoms, has the formula 1) C 6 H 14 2) C 6 H 12 3) C 6 H 10 4) C 6 H 6 2. The isomer of pentene-1 is 1) 2-methylbethene - 1 2) cyclopentane 3) penten-3 4) penten-2 3. Coefficient before the formulawater in the combustion reaction of propene 4. As a resulthydration butene-1 is formed 1) butanol-1 2) butanol-2 3) 1-methylbutene-1 4) 2-methylbutene-1 5. The qualitative reaction to alkenes is 1) hydrogenation 2) combustion 3) bromination 4) oxidation with potassium permanganate

Card 3. Topic: Alkenes 1. To classalkenes applies 1) C 5 H 12 2) C 7 H 14 3) C 6 H 10 4) C 7 H 16 2. How many isomers can exist for a substance with composition C 4 N 8 ? 3. Coefficient before the formulawater in the combustion reaction of butene 4. As a result of the addition of hydrogen bromide to butene-1 is formed 1) 1-bromobutane 2) 2-bromobutane 3) 1-bromobutene-1 4) 2-bromobutene-1 5. You can get propene by reaction 1) hydrogenation of butane 2) hydration of propine 3) propane dehydrogenation 4) hydrogenation of ethene

Card 4. Topic: Alkenes 1. Compositionalkenes reflects the general formula 1) C n H 2n+2 2) C n H 2n 3) C n H 2n-2 4) C n H 2n-6 2. The isomer of cis-butene-2 ​​is 1) methyl propane 2) trans-beten-2 3) methylcyclopropane 4) cyclobutane 3. Coefficient before the formulawater in the combustion reaction of pentene 4. As a result addition of hydrogen chloride to pentene-1 is formed 1) 1-chloropentane 2) 2-chloropentane 3) 1-chloropentene-1 4) 2-chloropentene-1 5. When ethylene is oxidized with potassium permanganate, it forms 1) carbon dioxide 4) ethylene glycol

This work is offered to students with the aim of monitoring the assimilation of program material on unsaturated hydrocarbons (alkynes and alkenes) and the tasks: to check the level of assimilation of nomenclature and isomerism, the ability to obtain alkenes and alkynes, to draw up reaction equations with their participation, to solve qualitative and calculation problems on these topics.

The work is compiled taking into account an individual approach:

Option 1 – lightweight;

Option 2 – intermediate level;

Option 3 – complicated.

Test

1 task

Option 1

What is the number of isomeric alkenes of composition C 5 H 10? Make up their formulas and name them.

Option 2.

Make up formulas of isomers for the proposed substance, name them, indicate the types of isomerism. 2,5-dimethylhexine-3

Option 3

Which of the proposed pairs of substances are isomers?

Name the substances, indicate the types of isomerism.

2 task

1 option .

Write down reaction equations and name all the substances.

Option 2.

Carry out the transformations, indicate the names of the substances, types of chemical reactions, conditions for their implementation:

Option 3.

The chain of transformations is given:

Carry out the transformations, name the substances, indicate the types of reactions.

3 task

1 option

How to recognize the following substances: ethane, ethene, ethyne?

Write down reaction equations.

Option 2.

Suggest a method for recognizing compounds: butane, butene - 1, propyne.

Write down reaction equations.

Option 3.

Suggest a method for recognizing substances: propane, pentene - 2, pentine - 2, pentine - 1.

Write the reaction equations.

4 task

Task.

1 option

How many liters of hydrogen will be required to completely hydrogenate 16.2 g of butine - 2?

Option 2

What mass of calcium carbide containing 15% impurities must be taken to obtain 40 liters of acetylene (n.o.)?

Option 3

Carbon dioxide produced by burning 8.4 liters of ethylene (n.o.) is passed through 472 ml of 6% NaOH solution (density = 1.06 g/ml). What is the composition of the resulting salt and what is its mass fraction in the solution?

Independent work on the topic “ALKYNE”.

1. For the compound 6-methylheptin-3, write the formulas of two homologues and 2 isomers.

2. Write down the reactions:

 Acetylene hydration

 Hydrogenation of 4-methylpentine-2

 Propine combustion

 Halogenation of 2,5 –dimethylhexine-3

 Bromination of butine-1

 Hydrogenation of 2,2,5-trimethylhexine-3

 Addition of hydrogen halide to propyne

 Polymerization of acetylene

 Methane dehydrogenation

 Ethylene dehydrogenation

8. What is formed when an alcohol solution of alkali reacts with 2,3-dibromoethane.

Write an equation for the reaction.

9. Carry out the chain:

Methane----ethylene----acetylene-----acetic aldehyde

1,2-dibromoethylene

10. Calculate the volume of acetylene that can be obtained from 130 g of calcium carbide,

Independent work on the topic “Alkadienes. Alkynes"

Option #1.

Make up the electronic and structural formula of the propyne molecule, determine the valence and st. oxidation of carbon atoms. Indicate the state of hybridization in which the carbon atom at the triple bond is located.

Using the example of the fifth member of the homologous series of alkynes, create structural formulas:

a) 2 isomers of the triple bond position;

c) 2 isomers from another homologous series. Name all isomers.

Carry out the transformations:

C 2 H 5 COONa C 2 H 6 C 2 H 4 C 2 H 2 X

When 4.1 g of hydrocarbon is burned, 13.2 g of carbon monoxide (IV) and 4.5 g of water are obtained. The vapor density of the substance for hydrogen is 41. Determine the formula of the substance.

_______________________________________________________________________

Option #2.

Make up the electronic and structural formula of the 2,3-dimethylbutadiene-1 molecule, determine the valence and st. oxidation of carbon atoms. Indicate the state of hybridization in which the carbon at the double bond is located.

Using the example of the sixth member of the homologous series of alkadienes, create structural formulas:

a) 2 isomers of bond positions;

b) 2 isomers of the carbon chain;

c) cis- and trans-isomers;

d) 2 isomers from another homologous series. Name all isomers.

3. Carry out transformations:

C 2 H 2 C 2 H 4 C 2 H 5 Br C 2 H 4 polymer

4. When 2.8 g of hydrocarbon is burned, 0.2 mol of carbon dioxide and 0.2 mol of water are obtained. 3.64 g of this substance occupies a volume of 1.456 l (n.s.). Determine the molecular formula of the substance.

Tests on the topic “Alkadienes. Alkynes"

1 .Pentine corresponds to the general formula:

a) C n H 2 n -6; b) C n H 2 n -2 ; c) C n H 2 n ; d) C n H 2 n +2

2 . The carbon-carbon bond length is the shortest in a molecule:

a) C 2 H 4 b) C 2 H 2 c) C 4 H 10 d) C 5 H 10.

3 . A hydrocarbon in which the orbitals of all carbon atoms are sp-hybridized:

a) propadiene; b) propine, c) ethine, d) butadiene – 1.3.

4. Pentadiene-1,4 and 2-methylbutadiene-1,3 are:

a) homologs, b) the same substance, c) geometric isomers, d) structural isomers.

5 . Saturated hydrocarbons do not differ from unsaturated hydrocarbons:

a) type of hybridization, b) solubility in water, c) the presence of different bonds between carbon atoms, d) the structure of molecules.

6 . The hydration reaction involves:

a) ethylene, butine-2, propadiene; b) propylene, pentane, ethyne;

c) butadiene -1,3, butane, cyclopropane; d) ethene, ethane, ethyne.

7 . The following interact with potassium permanganate:

a)methane, ethylene, propene; b) propadiene, 2-chloropropane, propene;

c) propyne, butene-2, butadiene-1.3 d) cyclopentane, ethylene, ethene.

8 . Acetylene does not interact with:

a) bromine water, b) hydrogen bromide,

c) an ammonia solution of silver (I) oxide, d) nitrogen.

9 . Pentin-1 and 2-methylpentadiene-1,3 can be recognized:

a) alcohol solution of sodium hydroxide, b) bromine water,

c) concentrated nitric acid, d) ammonia solution of silver (I) oxide.

10 . Bromine water is decolorized under normal conditions:

a) methane, ethene, ethyne, b) propyne, butadiene-1,3, cyclohexane,

c) butadiene-1,3, ethene, propyne, d) butane, butene-1, ethylene.

11. Pentin-1 and pentin-2 can be recognized:

a) potassium permanganate solution, b) bromine water, c) hydrogen chloride solution,

d) ammonia solution of copper (I) chloride.

12 . The volume of a portion of propyne (n.s.) containing 6 * 10 23 hydrogen atoms is:

a) 22.4 l, b) 5.6 l, c) 7.5 l, d) 11.2 l.

13 . For welding and cutting metals, gas is used in which the mass fraction of carbon and hydrogen is 92.31 and 7.69%, respectively. This is gas:

a) ethane, b) ethylene, c) acetylene, d) methane.

14 . For complete hydrogenation of 7.8 g of acetylene, you will need hydrogen in volume (n.s.)…..(l).

15. When 10 g of calcium carbide sample was treated with water, 2.24 liters of acetylene were obtained. The mass fraction of calcium carbide in the sample is ....(%).

16 . From 1,2-dichloropropane weighing 62.15 g, 10 l (n.s.) of propyne was obtained. The practical yield is….. (%).